SOLUTION: A radiator contains 6 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 60% antifreeze solution?

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Question 780824: A radiator contains 6 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 60% antifreeze solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Let C = capacity of the vessel
p = percent concentration initially filled in the vessel
T = percent concentration wanted filled in vessel after adjustment
h = percent concentation of material to add
v = volume of the p concentration material to drain and replace with the h material; unknown

{pure matter}/{total mixture}={concentration}

highlight%28%28Cp-vp%2Bvh%29%2FC=T%29
Simplify and solve for v.
Cp%2Bvh-vp=CT
v%28h-p%29=CT-Cp
highlight%28v=C%28T-p%29%2F%28h-p%29%29

Substitute according to
h=100 %
p=25 %
T=60 %
C=6 Liters
and then compute v for the exercise.