SOLUTION: 3 consecutive odd integers that four times the smallest is 56 more than the sum of the other two.

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Question 780350: 3 consecutive odd integers that four times the smallest is 56 more than the sum of the other two.
Answer by solver91311(24713) About Me  (Show Source):
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First integer , so next consecutive odd integer is and the one after that is

So



Solve for , then calcualte and

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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