SOLUTION: Solve for x: log3(x)+ 13log3 (x^4)= 14 the 3 is log base 3 My work: log3(x) + log3(x^4)^13 =14 log3(x) + log3(x^52) = 14 log3(x*x^52)=14 log3(x^53)=15 Then how do

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve for x: log3(x)+ 13log3 (x^4)= 14 the 3 is log base 3 My work: log3(x) + log3(x^4)^13 =14 log3(x) + log3(x^52) = 14 log3(x*x^52)=14 log3(x^53)=15 Then how do      Log On


   

Question 780344: Solve for x:
log3(x)+ 13log3 (x^4)= 14
the 3 is log base 3
My work:
log3(x) + log3(x^4)^13 =14
log3(x) + log3(x^52) = 14
log3(x*x^52)=14
log3(x^53)=15
Then how do you find x?
Answer by psbhowmick(878) About Me  (Show Source):