SOLUTION: can some please help me .And thanks in advance . 1 )I have to fine the slpoe of the line that passes through the points (-4,1)and (3,8). i believe the answer is M=-1/2 for # 1 w

Algebra ->  Equations -> SOLUTION: can some please help me .And thanks in advance . 1 )I have to fine the slpoe of the line that passes through the points (-4,1)and (3,8). i believe the answer is M=-1/2 for # 1 w      Log On


   



Question 78033This question is from textbook intermedia algebra
: can some please help me .And thanks in advance .
1 )I have to fine the slpoe of the line that passes through the points (-4,1)and (3,8). i believe the answer is M=-1/2 for # 1 waht do you all think please help me .
2)i have to fine the equation ,in slope-intercept form ,of the line that passes through the points (-5,2)and (-4,1)
This question is from textbook intermedia algebra

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
Hello.. here goes the solution.

find the slpoe of the line that passes through the points (-4,1)and (3,8).

The slope of the line passing thru 2 points (x1, y1) and (x2, y2) is given by:

m+=+%28y1+-+y2%29%2F%28x1+-+x2%29

Substituting for the points from the given data, we get:

+m+=+%288+-+1%29%2F%283+-+%28-4%29%29+

+m+=+%287%2F+7%29+

m = 1

This represents the slope of the line.

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find the equation in slope-intercept form , of the line that passes through the points (-5,2)and (-4,1)

The equation of the line in the slope intercept form is given by:

+y+-+y1+=+m%28x+-+x1%29 ------------(1)

Where m is the slope, which is given by: m+=+%28y1+-+y2%29%2F%28x1+-+x2%29

substituting the co-ordinates in the slope, we get:

+m+=++%281+-+2%29%2F%28-4+-%28-5%29%29+


+m+=+-1%2F1

==> m = -1

Now substitute the slope and the one of the co-ordinate in Equation (1). We get:

y - 2 = (-1)(x - (-5))

y - 2 = (-1)(x + 5)


y - 2 = - x - 5

y - 2 + x + 5 = 0

y + x + 3 = 0

represents the equation of the line in the slope intercept form.


hence, the solution.