SOLUTION: n^2-(4r+i)n+4r^2=?
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Question 780297
:
n^2-(4r+i)n+4r^2=?
Answer by
stanbon(75887)
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n^2-(4r+i)n+4r^2=?
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Using the Quadratic Formula::
n = [(4t+i)+-sqrt[(15+8i)-16r^2]/2
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Cheers
Stan H.
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