Question 780214: Hi, I really need help with this question. I urgently need an answer to this question. I have to use algebra to solve it.
Thanks
A man is nine times as old as his son. In nine years, he will be only three times as old as his son. How old are each now?
Please use the variables:
F = Age of father
S = Age of son
Any other variables can be included if need be.
Thanks so much!
Found 3 solutions by josmiceli, MathTherapy, lwsshak3:
Answer by josmiceli(19441)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Hi, I really need help with this question. I urgently need an answer to this question. I have to use algebra to solve it.
Thanks
A man is nine times as old as his son. In nine years, he will be only three times as old as his son. How old are each now?
Please use the variables:
F = Age of father
S = Age of son
Any other variables can be included if need be.
Thanks so much!
Let age of father, and son be F and S, respectively
Then: F = 9S ---- eq (i)
In 9 years, father's age then = F + 9, and son's will be S + 9
Since in 9 years he (father) will be only be three times as old as his son, then we can say that: F + 9 = 3(S + 9)
F + 9 = 3S + 27 ----- F - 3S = 18 ------ eq (ii)
9S - 3S = 18 ------- Substituting 9S for F in eq (ii)
6S = 18
S, or son's current age =  , or 
F = 9(3) ------ Substituting 3 for S in eq (i)
F, or father's current age = 
You can do the check!!
Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
Answer by lwsshak3(11628)  (Show Source):
You can put this solution on YOUR website! A man is nine times as old as his son. In nine years, he will be only three times as old as his son. How old are each now?
Please use the variables:
F = Age of father now
S = Age of son
***
F=9S
In 9 yrs:
F+9=Age of father now
S+9=Age of son now
..
F+9=3(S+9)
F+9=3S+27
9S+9=3S+27
6S=18
S=3
F=9S=27
Age of father now=27
Age of son now=3
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