SOLUTION: Please help me solve this equation: (15x^3-10x^2) over (3x^2-5x+2) I have no idea how to solve this so I can't provide any work that proves that I have tried doing it.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me solve this equation: (15x^3-10x^2) over (3x^2-5x+2) I have no idea how to solve this so I can't provide any work that proves that I have tried doing it.      Log On


   

Question 77996: Please help me solve this equation:
(15x^3-10x^2) over (3x^2-5x+2)
I have no idea how to solve this so I can't provide any work that proves that I have tried doing it.
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve this equation:
(15x^3-10x^2) over (3x^2-5x+2)
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It is not an equation so it has no "solution".
Maybe you were asked to "simplify" it.
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Factor where you can to get:
(5x^2(3x-2))/(3x+1)(x-2))
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There are no factors common to numerator and denominator
so no cancelling can be done.
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Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%2815x%5E3-10x%5E2%29%2F%283x%5E2-5x%2B2%29

%285x%5E2%283x-2%29%29%2F%283x%5E2-5x%2B2%29 Factor out 5x^2 on the numerator
Now factor the denominator:
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.
Error occurred executing solver 'quadratic_factoring' .


So we get the expression
%285x%5E2%283x-2%29%29%2F%28%283x-2%29%28x-1%29%29

%285x%5E2cross%28%283x-2%29%29%29%2F%28cross%28%283x-2%29%29%28x-1%29%29 Notice the terms 3x-2 cancel
which leaves us with this:
%285x%5E2%29%2F%28x-1%29
So the expression %2815x%5E3-10x%5E2%29%2F%283x%5E2-5x%2B2%29 reduces to

%285x%5E2%29%2F%28x-1%29

As always, you can graph the two expressions as equations and they will be the same. This means they are equivalent.