SOLUTION: My teacher says there is a smaller x-value and a larger x-value for this problem. However, the only x-value I come up with is 1, the larger x-value. How can there be two x-values?
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Question 779264: My teacher says there is a smaller x-value and a larger x-value for this problem. However, the only x-value I come up with is 1, the larger x-value. How can there be two x-values? (x+7)^(4/3)=16 Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! (x+7)^(4/3) = 16
Cube both sides and you have
(x+7)^4 = 4096
Find the 4th root of both sides
x + 7 = +/-
Two solutions
x + 7 = +8
x = 1
and
x - 7 = -8
x = -8 - 7
x = -15 is the 2nd solution
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Check this in your calc: enter (-15+7)^(3/4) results is 16
