SOLUTION: i. P(Z < -0.2) ii. P(-2.03 < z < 2.3)
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Question 779183
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i. P(Z < -0.2)
ii. P(-2.03 < z < 2.3)
Answer by
stanbon(75887)
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i. P(Z < -0.2) = normalcdf(-100,-0.2) = 0.4207
ii. P(-2.03 < z < 2.3) = normalcdf(-2.03,2.3) = 0.9681
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Cheers,
Stan H.
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