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Question 778844: 4 digit numbers ending in 8 is the product of 3 consecutive even numbers.find the number
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! 4 digit numbers ending in 8 is the product of 3 consecutive even numbers.
find the number.
:
Let n = the first number
:
n * (n+2) * (n+4) = n(n^2 + 4n + 2n + 8) = n^3 + 6n^2 + 8n
:
The table for this equation, has only one 4 digit number ending in 8, n=12
12*14*16 = 2688 is the number
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