SOLUTION: the difference between two numbers is 13.Twice the smaller plus three times the larger is 129.What are the numbers?

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Question 778550: the difference between two numbers is 13.Twice the smaller plus three times the larger is 129.What are the numbers?
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the difference between two numbers is 13.Twice the smaller plus three times the larger is 129.What are the numbers?
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Equations:
x - y = 13
2x + 3y = 129
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Modify for elimination:
2x - 2y = 26
2x + 3y = 129
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Subtract and solve for "y":
5y = 103
y = 103/5
----
Solve for "x":
x - (103/5) = (65/5)
x = 168/5
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Cheers,
Stan H.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

the difference between two numbers is 13.Twice the smaller plus three times the larger is 129.What are the numbers?

Let the larger number be L

Then the smaller = L - 13

We then have: 2(L - 13) + 3L = 129

2L - 26 + 3L = 129

2L + 3L = 129 + 26

5L = 155

L, or larger number = 155%2F5, or highlight_green%2831%29

Smaller number = 31 - 13, or highlight_green%2818%29

You can do the check!!

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