Question 77847: Science and medicine.
A passenger train can travel 325 mi in the same time a
freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster than the speed of the freight train, find the speed of each.
thanks
Answer by vertciel(183)   (Show Source):
You can put this solution on YOUR website! Hello there,
Let's set up a chart so we can visualise clearly the informatio known to us:
| Distance | Speed | Time |
Passenger Train | 325 | | t |
Freight Train | 200 | | t |
The distance is 325 and 200 respectively as stated by the question, and times are equal as stated by the question.
We do not know speed, so we want to find it! We can express speed in terms of the other two variables. Recall d = st, so s = d/t.
| Distance | Speed | Time |
Passenger Train | 325 | 325/t | t |
Freight Train | 200 | 200/t | t |
Since the questions says that if the freight train's speed was faster by 25 mi/h, we can set up this equation:
325/t = 200/t + 25
Solving for t:
325/t - 200/t= 25
125/t = 25
t = 25
Since the passenger train's speed is 325/t, you can substitute t in, so you get 325/5 = passenger's train = 65 mi/h.
See if you can find the speed of the freight train.
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