SOLUTION: without using table, prove that log (351/539) + 2log (91/110) - 3log (39/110)=1 (base are same 10)

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Question 777873: without using table, prove that
log (351/539) + 2log (91/110) - 3log (39/110)=1

(base are same 10)

Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
We can either do it by expanding the logs or by
compressing the logs.  We will choose to compress
them:

log%28%28351%2F539%29%29%2B2log%28%2891%2F110%29%29-3log%28%2839%2F110%29%29 

To make things easier, let's get the third term positive
by inverting the fraction and raising the fraction to
the -1 power:

log%28%28351%2F539%29%29%2B2log%28%2891%2F110%29%29-3log%28%28110%2F39%29%5E%28-1%29%29 =

Then we can bring the -1 power out in front of the log as 
a multiplier and the coefficient will be positive:

log%28%28351%2F539%29%29%2B2log%28%2891%2F110%29%29%2B3log%28%28110%2F39%29%29 =

Break all the integers into prime factors:

 =

Write the coefficients of the logs as exponents: 

 =

Raise each factor inside the parenthesesto the exponent outside 
the parentheses:

 =

Write the sum of the three logs as the log of their product

 =

Multiply the three fractions:

 =

Add exponents of 13 in the top and of 11 in the bottom:

 =

Cancel like factors in the numerator and denominator:

 =

log%28%28+%282%5E3%2A5%5E3%29%2F%282%5E2%2A5%5E2%29%29%29 =

Subtract exponents

log%28%282%2A5%29%29 =

log%28%2810%29%29 =

      1

Edwin