SOLUTION: Find four consecutive integers such that three times the sum of the last two exceeds twice the sum of the first two by 31?

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Question 777865: Find four consecutive integers such that three times the sum of the last two exceeds twice the sum of the first two by 31?
Answer by mananth(16946) About Me  (Show Source):
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Find four consecutive integers such that three times the sum of the last two exceeds twice the sum of the first two by 31?
let the numbers be x,x+1,x+2,x+3
3(x+2+x+3)=2(x+x+1)+31
3(2x+5)=2(2x+1)+31
6x+15=4x+2+31
6x-4x=-15+2+31
2x=18
/2
x=9
9,10,11,12