SOLUTION: There are 5 white balls, 8 black balls, and 1 red ball in a box. How many red balls would have to be added to the box for the probability of drawing a red ball to become 5/6?

Algebra ->  Probability-and-statistics -> SOLUTION: There are 5 white balls, 8 black balls, and 1 red ball in a box. How many red balls would have to be added to the box for the probability of drawing a red ball to become 5/6?      Log On


   



Question 777851: There are 5 white balls, 8 black balls, and 1 red ball in a box. How many red balls would have to be added to the box for the probability of drawing a red ball to become 5/6?
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
(x+1)/(x+14)=5/6
solving for x yields 64, so add 64 red balls