SOLUTION: John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way?
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Question 777742: John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way?
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let x=driving speed to dayton
x+26=driving speed on return trip
distance=speed*travel time
..
5x=3(x+26)
5x=3x+78
2x=78
x=39
x+26=65
driving speed to dayton=39 mph
driving speed on return trip=65 mph
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