SOLUTION: EAch of the two congruent sides of an isosceles triangle is 7 cm longer than half the base. Find the length of each side of the triangle.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: EAch of the two congruent sides of an isosceles triangle is 7 cm longer than half the base. Find the length of each side of the triangle.      Log On


   



Question 777654: EAch of the two congruent sides of an isosceles triangle is 7 cm longer than half the base. Find the length of each side of the triangle.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
There are two many triangles, with different measurements that comply with that.
Here are 3 examples:

Either you are missing some information, or you are expected to say that there are infinte solutions. If you had some other information, like the height, or one angle, you could start by
x= half the base
x%2B7= length of the congruent sides,
and then use that with any extra information

IF it were a highlight%28right%29 isosceles triangle,
then the base is the hypotenuse, with length 2x and the congruent sides are the legs.
Then, Pythagoras says
%28x%2B7%29%5E2%2B%28x%2B7%29%5E2=%282x%29%5E2
2%28x%2B7%29%5E2=4x%5E2
2%28x%5E2%2B14x%2B49%29=4x%5E2
2x%5E2%2B28x%2B96=4x%5E2
0=2x%5E2-28x-96
Flipping, and dividing both sides by 2
0=2x%5E2-28x-96 --> 2x%5E2-28x-96=0 --> x%5E2-14x-49=0
The solutions to that equation are
x=7+%2B-+7sqrt%282%29
The solution with the negative sign is a negative number, which could not be the length of half the base,
so x=7+%2B+7sqrt%282%29 and x%2B7=+14%2B7sqrt%282%29=about23.9%28rounding%29