SOLUTION: A wire 264 cm in length is to be cut into two pieces, one to form a rectangle whose length is four less than twice the width, and the other to form a square whose side is equal to
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Question 777611: A wire 264 cm in length is to be cut into two pieces, one to form a rectangle whose length is four less than twice the width, and the other to form a square whose side is equal to the sum of the width and the length of the rectangle. How long is the shorter of the cut pieces of the wire? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! A wire 264 cm in length is to be cut into two pieces, one to form a rectangle whose length is four less than twice the width, and the other to form a square whose side is equal to the sum of the width and the length of the rectangle. How long is the shorter of the cut pieces of the wire?
one to form a rectangle whose length is four less than twice the width,
let width be x
then length 2x-4
Perimeter = 2(x+2x-4)
=2(3x-4)
=6x-8
a square whose side is equal to the sum of the width and the length of the rectangle.
side of square = x+(2x-4)
Perimeter = 4(x+(2x-4))
=4(3x-4)
=12x-16
Perimeter of square + perimeter of rectangle = length of wire
6x-8+12x-16=264
18x-24=264
18x=264+24
18x=288
/18
x=16
perimeter of rectangle = 6x-8
=16*6-8=88 cm
perimeter of square = 12x-16
=12*16-16
=192-16
=176 cm
length of two parts 88 & 176 cm
