Question 777160: determine the quadratic function f who vertex is 2,-1 and passes through 1,2 type the answer in ax^2+bx+c
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! determine the quadratic function f who vertex is 2,-1 and passes through 1,2 type the answer in ax^2+bx+c
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vertex form of equation for a parabola:
y=A(x-h)^2+k
For given function:
using given coordinates of the vertex(2,-1)
y=A(x-2)^2-1
using given coordinates of given point on the curve(1,2)
2=A(1-2)^2-1
A=3
equation:
y=3(x-2)^2-1
y=3(x^2-4x+4)-1
y=3x^2-12x+12-1
y=3x^2-12x+11
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