SOLUTION: Using the Pythagorean theorem, how do I solve for x in the following equation?
x^2 + (2x + 4)^2 = (2x + 6)^2
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x^2 + (2x + 4)^2 = (2x + 6)^2
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Question 777044: Using the Pythagorean theorem, how do I solve for x in the following equation?
x^2 + (2x + 4)^2 = (2x + 6)^2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve for x in the following equation?
x^2 + (2x + 4)^2 = (2x + 6)^2
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x^2 + 4x^2 + 16x + 16 = 4x^2 + 24x + 36
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x^2 -8x -20 =
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x^2 -10x + 2x -20 = 0
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x(x-10) + 2(x-10) = 0
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(x-10)(x+2) = 0
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Cheers,
Stan H.
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