SOLUTION: The expression 5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t where r, the exponent of h, is: and t, the exponent of s, is: and k, the l

Algebra ->  Radicals -> SOLUTION: The expression 5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t where r, the exponent of h, is: and t, the exponent of s, is: and k, the l      Log On


   

Question 776783: The expression
5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coefficient is:<--- which I know is 2
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t
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5th root of [32h^7s^8] = 2hs*5th root of (h^2*s^3)
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where r, the exponent of h, is: 2
and t, the exponent of s, is: 3
and k, the leading coefficient is:<--- which I know is 2
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Cheers,
Stan H.
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