Question 776691: Hello,
I need help getting started with this word problem. I already know the answer; Darwin has 36 nickels, 18 dimes, and 11 quarters. I just want to figure out how.
Darin has just emptied his piggy bank filled with nickels, dimes, and quarters worth $6.35. If there are seven more dimes than quarters, and twice as many nickels as dimes, how many of each type of coin does he have?
x=Quarters
2x=Nickels
x+7=Dimes
So...assuming the above is correct, is it 2x+x+7=6.35? After that I did .25(x)=.25x
.05(2x)=.1x
.1(x+7)=.1+.7
.25x+.1x+.1x+.7=6.35
I tried solving it and got 12.555, and that does not seem right. Please help, what did I do wrong?
Answer by fcabanski(1391)   (Show Source):
You can put this solution on YOUR website! You have it written as twice as many nickles as quarters. Quarters is x. You have nickles as 2x. That's not correct.
The problem indicates there are twice as many nickels as dimes. There are x+7 dimes, so there are 2(x+7) nickels.
Solve it from there.
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