SOLUTION: Solve = 2x2(square) + 3 = 7x

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Question 77656: Solve =
2x2(square) + 3 = 7x
Found 2 solutions by tutorcecilia, praseenakos@yahoo.com:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%5E2+%2B+3%29 = %287x%29
%282x%5E2-7x+%2B+3%29 = %280%29 [Isolate all of the terms to one side and set the equation equal to zero]
.
%282x-1%29%28x-3%29%29 = %280%29 [factor]
(2x-1=0 [set each factor equal to zero and solve for x]
2x-1=0
2x=1
x=1/2
.
(x-3)=0
x-3=0
x=3
.
Check by plugging either value of x back into the original equation and solve.

Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
Question:

2x^2 + 3 = 7x

Answer:

2x^2 + 3 = 7x


2x^2 + 3 - 7x = 7x - 7x , subtract 7x from both sides.


==> 2x^2 - 7x + 3 = 0


Now split the middle term, that is -7x.


For that find two numbers whose sum is -7(that is coefficient of x ) and their product is 6 (that is 2* 3 )


Such two numbers are -6 and -1


==> 2x^2 -6x - 1x + 3 = 0

Now group the terms


==> 2x ( x - 3 ) - ( x-3) = 0


==> (x - 3 )( 2x - 1) = 0


==> Either (x - 3 ) = 0 or (2x - 1 ) = 0


==> x = 3 or 2x = 1


==> x = 3 or x = 1/2



These are the solutions of the given polinomial.


Hope you understood.


Regards.

Praseena.