|
Question 776407: Hi, if anyone could help me with this. I would really appreciate it.
A group of neighbors agreed to contribute equally toward the purchase of some garden equiptment costing $72. When the equiptment was delivered, two others asked to join the group. The result was that each person contributed $1.80 less than originally planned. How many were in the original group?
Thank you for the help! Kudos!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A group of neighbors agreed to contribute equally toward the purchase of some garden equiptment costing $72. When the equiptment was delivered, two others asked to join the group. The result was that each person contributed $1.80 less than originally planned. How many were in the original group?
-------
Let the original # of people be "x"::
Average cost for them would be 72/x dollars.
---------
Average cost with 2 additional people:: 72/(x+2)
---------
Equation:
original average - new average = 1.80
72/x - 72/(x+2) = 1.8
-----
1/x - 1/(x+2) = 0.025
------------
x+2 - x = 0.025x(x+2)
-------
0.025x^2+0.05x-2 = 0
-------
x = 8 (original # of people)
================================
Cheers,
Stan H.
==============
|
|
|
| |
