SOLUTION: in a certain town, 40% of the people have brown hair, 25% have brown eyes,and 15% have both brown hair and brown eyes. a person is selected at a random from the town. if he has bro

Algebra ->  Probability-and-statistics -> SOLUTION: in a certain town, 40% of the people have brown hair, 25% have brown eyes,and 15% have both brown hair and brown eyes. a person is selected at a random from the town. if he has bro      Log On


   



Question 776267: in a certain town, 40% of the people have brown hair, 25% have brown eyes,and 15% have both brown hair and brown eyes. a person is selected at a random from the town. if he has brown eyes, what is the probability that he does not have brown hair?
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
BE = Brown eyes
BH = Brown hair
We know:
P(BH)=0.4
P(BE)=0.25
P(BH and BE) = 0.15

We want to know: P(BH/BE)
P(BH/BE)= P(BH and BE)/P(BE) = 0.15/0.4 = 0.375
Answer: 0.375

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