SOLUTION: If sin A and cos A are the roots of the equation ax^2 - bx + c = 0, then a, b and c satisfy the equation:
(A) b^2 - a^2 = 2ac
(B) a^2 - b^2 = 2ac
(C) a^2 + b^2 = c^2
(D) a^2 +
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-> SOLUTION: If sin A and cos A are the roots of the equation ax^2 - bx + c = 0, then a, b and c satisfy the equation:
(A) b^2 - a^2 = 2ac
(B) a^2 - b^2 = 2ac
(C) a^2 + b^2 = c^2
(D) a^2 +
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Question 776264: If sin A and cos A are the roots of the equation ax^2 - bx + c = 0, then a, b and c satisfy the equation:
(A) b^2 - a^2 = 2ac
(B) a^2 - b^2 = 2ac
(C) a^2 + b^2 = c^2
(D) a^2 + b^2 = 2ac Answer by tommyt3rd(5050) (Show Source):
You can put this solution on YOUR website! A:
The algebra is tedious, but manageable. Use the pythagorean trig identity for sine and cosine set equal to the squares of the 2 roots written in quadratic equation form. Expand and simplify.
