SOLUTION: I am not sure how to set this word problem up in order to solve.
Joan has a pocketful of dimes and quarters worth $2.95. If there are 22 coins in all, how many are quarters?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: I am not sure how to set this word problem up in order to solve.
Joan has a pocketful of dimes and quarters worth $2.95. If there are 22 coins in all, how many are quarters?
Log On
Question 776065: I am not sure how to set this word problem up in order to solve.
Joan has a pocketful of dimes and quarters worth $2.95. If there are 22 coins in all, how many are quarters? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! .10x +.25y = 2.95
x + y = 22
y = 22 -x
==========================================
.10x +.25(22 -x) = 2.95
.10x +5.5 -.25x = 2.95
-.15x = -2.55
x = 17 dimes
y = 5 quarters