SOLUTION: I am not sure how to set this word problem up in order to solve. A merchant has coffee worth $5 a pound that she wishes to mix with 9 pounds of coffee worth $3 a pound to get a

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: I am not sure how to set this word problem up in order to solve. A merchant has coffee worth $5 a pound that she wishes to mix with 9 pounds of coffee worth $3 a pound to get a       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 775974: I am not sure how to set this word problem up in order to solve.
A merchant has coffee worth $5 a pound that she wishes to mix with 9 pounds of coffee worth $3 a pound to get a mixture that can be sold for $2 a pound. How many pounds of $5 coffee should be mixed

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of $5 coffee needed
+5x+ = cost of the $5 coffee
+3%2A9+=+27+ = cost of the $3 coffee
--------------
+%28+5x+%2B+27+%29+%2F+%28+x+%2B+9+%29+=+2+
+5x+%2B+27+=+2%2A%28+x+%2B+9+%29+
+5x+%2B+27+=+2x+%2B+18+
+3x+=+-9+
+x+=+-3+
The negative answer tells me it can't be solved.
Logically, there is no way you can mix $5/pound
coffee with $3/pound coffee and end up with
$2/pound coffee
----------------
The cost/pound of the final mixture has to be
somewhere between $3 and $5