SOLUTION: The sum of five consecutive even integers is 210. The largest of these even integers is?

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Question 775725: The sum of five consecutive even integers is 210. The largest of these even integers is?
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive even integers be: 2n-4, 2n-2, 2n, 2n+2 and 2n+4.

The sum is 210.
(2n-4)+(2n-2)+2n+(2n+2)+(2n+4) = 210
10n = 210
n = 21

So the greatest of the 5 consecutive integer is 2x21+4 = 46.