I'm having a hard time making an equation for this problem. Please explain how to solve this: The sum of the squares of two numbers is 18
x2 + y2 = 18
and their product is 2.
xy = 2
Solve the system:
x2 + y2 = 18
xy = 2
Solve the second for y
y =
Substitute in the first:
x2 +
2 = 18
x2 +
= 18
Multiply through by x2
x4 + 4 = 18x²
x4 - 18x2 + 4 = 0
Solve that by the quadratic formula for x2
and then take square roots you get
one of them is approximately 4.216 and the other is
approximately 0.474, or they could be the negatives of those.
if their difference is 3, find the difference of their cubes.
Since their difference is not 3, the problem is botched. You
don't need to continue. Point this error out to your teacher.
Edwin