SOLUTION: I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8 I kind of remember this from algebra 1 but not quite. Don't I have to multiply everything by the common denominat

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Question 774814: I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8
I kind of remember this from algebra 1 but not quite. Don't I have to multiply everything by the common denominator? I'm confused. Thanks
Found 2 solutions by rothauserc, MathTherapy:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8
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first let's put the numerators on either side of the = over a common denominator
(x-5+1) / 2 = (16x - (x-3)) /8
(x-4) / 2 = (15x + 3) / 8
now cross multiply the fractions
8x -32 = 30x +6
-22x = 38
x = -38/22
x = -19/11

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8
I kind of remember this from algebra 1 but not quite. Don't I have to multiply everything by the common denominator? I'm confused. Thanks

Yes, you do!! That's the easiest way to approach the problem so you can get rid of the fractions

%28x+-+5%29%2F2+%2B+1%2F2+=+2x+-+%28x+-+3%29%2F8

4(x - 5) + 4 = 16x - (x - 3) ------ Multiplying by LCD, 8

4x - 20 + 4 = 16x - x + 3

4x - 16 = 15x + 3

4x - 15x = 3 + 16

- 11x = 19

x = 19%2F%28-+11%29, or highlight_green%28-+1%268%2F11%29

You can do the check!!

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