|
Question 77479: I searched all over the site, but I could not find anything similar to this question. How do I figure this out? Thanks in advance for you time and help.
Given a line containing the points (1,4), (2,7), and (3,10) determine the slope-intercept form of the equation, provide one additional point on this line, and graph the function.
Answer by checkley75(3666)   (Show Source):
You can put this solution on YOUR website! THE SLOPE IS (Y2-Y1/(X2-X1) THUS WE HAVE
(7-4)/(2-1)=3/1 OR A SLOPE OF 3.
NOW USING ONE SET OF POINTS SOLVE FOR THE Y INTERCEPT (b) IN THE EQUATION
Y=mX+b (m)= SLOPE
10=3*3+b
10=9+b
b=10-9
b=1 THUS THE LINE EQUATION IS
Y=3X+1.
NOW SETTING X=4 & SOLVING FOR Y WE GET
Y=3*4+1
Y=12+1
Y=13 OR THE ADDITIONAL POINT IS (4,13).
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x +1).
|
|
|
| |
