SOLUTION: THE SPEED OF A MOVING WALKWAY IS TYPICALLY ABOUT 3.6 PER SECOND. WALKING ON SUCH A MOVING WALKWAY, IT TAKES KAREN A TOTAL OF 50 SECONDS TO TRAVEL 90 FEET WITH THE MOVEMENT OF THE W

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: THE SPEED OF A MOVING WALKWAY IS TYPICALLY ABOUT 3.6 PER SECOND. WALKING ON SUCH A MOVING WALKWAY, IT TAKES KAREN A TOTAL OF 50 SECONDS TO TRAVEL 90 FEET WITH THE MOVEMENT OF THE W      Log On

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Question 774569: THE SPEED OF A MOVING WALKWAY IS TYPICALLY ABOUT 3.6 PER SECOND. WALKING ON SUCH A MOVING WALKWAY, IT TAKES KAREN A TOTAL OF 50 SECONDS TO TRAVEL 90 FEET WITH THE MOVEMENT OF THE WALK AWAY AND THEN BACK AGAIN AGAINST THE MOVEMENT OF THE WALKAWAY. WHAT IS KAREN'S NORMAL WALKING SPEED?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
THE SPEED OF A MOVING WALKWAY IS TYPICALLY ABOUT 3.6 ft PER SECOND.
WALKING ON SUCH A MOVING WALKWAY, IT TAKES KAREN A TOTAL OF 50 SECONDS TO TRAVEL 90 FEET WITH THE MOVEMENT OF THE WALK AWAY AND THEN BACK AGAIN AGAINST THE MOVEMENT OF THE WALKAWAY.
WHAT IS KAREN'S NORMAL WALKING SPEED?
:
Let w = the walking speed
then
(w+3.6) = ground speed with walkway
and
(w-3.6) = ground speed against
:
Write a time equation, time = dist/speed
:
time with + time against = 50 sec
90%2F%28%28w%2B3.6%29%29 + 90%2F%28%28w-3.6%29%29 = 50
multiply by (w-3.6)(w+3.6) results:
90(w-3.6) + 90(w+3.6) = 50(w-3.6)(w+3.6)
90w - 324 + 90w + 324 = 50(w^2 - 12.96)
180w = 50w^2 - 648
a quadratic equation
0 = 50w^2 - 180w - 648
Use the quadratic formula; a=50; b=-180; c=-648
I got a positive solution of 5.825 ft/sec as K's walking speed
See what you get