SOLUTION: Sheila and May are on opposite sides of a lake. Sheila's boat travels at 12 km/h and May's boat travels at 10 km/h. If the lake is 69 km wide, Sheila leaves at 1 pm, and May leaves
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Sheila and May are on opposite sides of a lake. Sheila's boat travels at 12 km/h and May's boat travels at 10 km/h. If the lake is 69 km wide, Sheila leaves at 1 pm, and May leaves
Log On
Question 774457: Sheila and May are on opposite sides of a lake. Sheila's boat travels at 12 km/h and May's boat travels at 10 km/h. If the lake is 69 km wide, Sheila leaves at 1 pm, and May leaves at 1:15pm, what time will they meet? Please solve step by step and explain. Thanks Answer by josgarithmetic(39621) (Show Source):
You can put this solution on YOUR website! The sum of their distances when they meet will be 69 km. Do you want to focus on a number line, or do you want to focus on time quantity?
Try looking at time quantity. May travels less time than Sheila, because May began her trip LATER than Sheila. Note that the difference between 1 pm and 1:15 pm is (1/4) of an hour. ... THINK how this seems correct.
...
Let h = time that May travels. This means that h+1/4 is the time in hours that Sheila travels. ..., again, THINK how this seems correct.
...
READY?
Make a data table.
Rower_________speed,km/hour ______time__________distance, km.
Sheila_________12________________h+1/4_________
May____________10_________________h_____________
TOTAL___________________________________________
Can you study all that and understand the process?
Can you use the information in the data table and see the equation to form?
Can you solve the equation for h?
Finally, use h to get the time of the day that they meet?
(