SOLUTION: Prove the conjecture below by writing a variable statement and using algebra.
Conjecture: the sum of 4 consecutive integers is always divisible by five.
X+(x+1)+(x+2)+(x+3)+(x+4)
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Conjecture: the sum of 4 consecutive integers is always divisible by five.
X+(x+1)+(x+2)+(x+3)+(x+4)
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Question 774136: Prove the conjecture below by writing a variable statement and using algebra.
Conjecture: the sum of 4 consecutive integers is always divisible by five.
X+(x+1)+(x+2)+(x+3)+(x+4)= ? Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! = the first integer
So the sum of the 5 consecutive integers is = an integer, actually, the third of the 5 consecutive integers,
so is a multiple of 5.