SOLUTION: Can someone please explain to me how to find the missing numerator in the equation, 2/3x=?/12x^3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can someone please explain to me how to find the missing numerator in the equation, 2/3x=?/12x^3      Log On


   



Question 774031: Can someone please explain to me how to find the missing numerator in the equation,
2/3x=?/12x^3

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You are seeming to want to find c in an equation, 2%2F3x=c%2F12x%5E3.

The left side is EQUAL to the right hand side. If we multply both sides of the equation by the same factor, then we still have equality. We can undo the division by 12x%5E3 on the right side by MULTIPLYING by 12x%5E3. We must do this to both the left hand member AND the right hand member.

%282%2F3x%29%2812x%5E3%29=%28c%2F12x%5E3%29%2812x%5E3%29
%282%2A12%2Ax%5E3%29%2F%283x%29=c
%282%2A4%2Ax%5E2%29=c
highlight%28c=8x%5E2%29


ANOTHER WAY BUT NOT WHAT YOU NEED FOR YOUR QUESTION:
If you multiply the left side member by 1, then this does not change the meaning or value of the left side member. How do we do this so the denominator will be 12x%5E3?

Denominator on the left member is 3*x
Denominator on the right member is 3*4*x*x*x
What factors and their counts are missing from the left hand side member? It needs 4, x, and another x.
We want a factor of 1 in the form of %284x%5E2%29%2F%284x%5E2%29

Now we can do this multiplication by 1:
%282%2F%283x%29%29%2A%28%284x%5E2%29%2F%284x%5E2%29%29
%282%2A4x%5E2%29%2F%283x%2A4x%5E2%29
and remember we are trying to multiply here to obtain the right hand side,
highlight%28%288x%5E2%29%2F%2812x%5E3%29%29, the equivalent fraction.
So our value for c, the numerator, is highlight%288x%5E2%29

This is the usual way you would look for equivalent fractions in elementary school education, but once we become acquainted with using variables, we can often more easily use the idea of reciprocals, or multiplicative inverses for proportions.