SOLUTION: ONE OF THE EXTERIOR ANGELS OF A TRIANGLE IS 80 DEGREE AND THE INTERIOR OPPOSITE ANGELS ARE IN THE RATIO 3:5.FIND THE ANGELS. PLEASE FAST IN 1 HR.

Algebra ->  Triangles -> SOLUTION: ONE OF THE EXTERIOR ANGELS OF A TRIANGLE IS 80 DEGREE AND THE INTERIOR OPPOSITE ANGELS ARE IN THE RATIO 3:5.FIND THE ANGELS. PLEASE FAST IN 1 HR.       Log On


   

Question 773916: ONE OF THE EXTERIOR ANGELS OF A TRIANGLE IS 80 DEGREE AND THE INTERIOR OPPOSITE ANGELS ARE IN THE RATIO 3:5.FIND THE ANGELS.
PLEASE FAST IN 1 HR.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3x+5x = 80

8x = 80

x = 80/8

x = 10

So 3x = 3*10 = 30 and 5x = 5*10 = 50

The two opposite interior angles (aka the remote interior angles) are 30 degrees and 50 degrees.