SOLUTION: irregular shaped ponds
What is the volume (in L) of the pond?
Volume (inL) = 2/3 x (length x width x average depth) x 1000
Length is 6m, height is 10m, average depth is 0
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-> SOLUTION: irregular shaped ponds
What is the volume (in L) of the pond?
Volume (inL) = 2/3 x (length x width x average depth) x 1000
Length is 6m, height is 10m, average depth is 0
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Question 773691: irregular shaped ponds
What is the volume (in L) of the pond?
Volume (inL) = 2/3 x (length x width x average depth) x 1000
Length is 6m, height is 10m, average depth is 0.6m Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! What is the volume (in L) of the pond?
Volume (inL) = 2/3 x (length x width x average depth) x 1000
I don't know where that's from.
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Length is 6m, height is 10m, average depth is 0.6m
If width = height, use the equation above ??
Multiply the numbers.
(2/3)*6*10*0.6*1000