SOLUTION: A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job. how many more days will the remaining men finish the job?
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Question 773494: A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job. how many more days will the remaining men finish the job? Found 4 solutions by 12217B, MathTherapy, josgarithmetic, ikleyn:Answer by 12217B(1) (Show Source):
A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job. how many more
days will the remaining men finish the job?
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What the other person has for an answer makes absolutely NO SENSE. How can it take 2 men, just 6 days to complete a job that
a group of 5 men, who normally take 10 days to complete the job, worked for 4 days, and then left the 2 men to complete?
5-MAN rate:
1-MAN rate:
2-MAN rate:
Formula: (Time 1 * rate 1) + Time 2 * rate 2) = 1 (entire job)
10 + T = 25 ---- Multiplying by LCD, 25
Time taken for remaining 2 men to complete job, or T = 25 - 10 = 15 days
You can put this solution on YOUR website! .
A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job.
how many more days will the remaining men finish the job?
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I will show another way to solve, using different method.
Its advantage is that the fractions or equations are not used.
The total job is 5 men * 10 days = 50 man-days.
In the first 4 days, 5 men used 5*4 = 20 man-days; 50 - 20 = 30 man-days work remained.
Now only 5 - 3 = 2 men work. They need 30/2 = 15 days to complete the remaining job.
So, the remaining 2 men will finish the rest of the job in 15 days. <<<---=== ANSWER
Solved completely, using mental reasoning instead equations and/or fractions.