SOLUTION: Find the exact values of all solutions in the interval 0<x<2pi for sin(x+(pi/4))+sin(x-(pi/4))=-1

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of all solutions in the interval 0<x<2pi for sin(x+(pi/4))+sin(x-(pi/4))=-1      Log On


   



Question 773421: Find the exact values of all solutions in the interval 0 sin(x+(pi/4))+sin(x-(pi/4))=-1
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

               sin(x + pi%2F4) + sin(x - pi%2F4) = -1

sin(x)cos(pi%2F4) + cos(x)sin(pi%2F4) + sin(x)cos(pi%2F4) - cos(x)sin(pi%2F4) = -1

2nd and 4th terms on the left cancel, 1st and 3rd terms are the same:

               2sin(x)cos(pi%2F4) = -1

               sin(x)cos(pi%2F4) = -1%2F2

and since cos(pi%2F4) = sqrt%282%29%2F2

               sin(x)·sqrt%282%29%2F2 = -1%2F2

Multiply both sides by 2

               sin(x)·√2 = -1

               sin(x) = -1%2F%28sqrt%282%29%29

               sin(x) = -1%2F%28sqrt%282%29%29·sqrt%282%29%2Fsqrt%282%29

               sin(x) = -sqrt%282%29%2F2

               x = 5pi%2F4, 7pi%2F4 

Edwin