SOLUTION: What is the slope-intercept form of a line passing through (6, 7) that is perpendicular to the line 2x - 5y = 7?
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Question 773323: What is the slope-intercept form of a line passing through (6, 7) that is perpendicular to the line 2x - 5y = 7? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! First sort out your equation
into y = mx + c form.
2x - 5y = 7
-5y = - 2x + 7
5y = 2x - 7
y = 2/5x - 7/5
Slope (m) is 2/5.
Lines that are perpendicular to
one another have slopes (m)
that multiply together to give
-1.
m1 * m2 = -1
2/5 * m2 = - 1
m2 = -5/2
Using the equation:
y - b = m(x - a) and coords (6,7)
a = 6, b = 7 and m = -5/2
y - 7 = -5/2(x - 6)
y - 7 = -5/2x + 30/2
y - 7 = -5/2x + 15
y = -5/2x + 15 + 7
y = -5/2x + 22
OR
Multiply thro' by 2
2y = -5x + 44
Hope this helps.
:-)
