SOLUTION: Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91.

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Question 773239: Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91.
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 3 consecutive odd integers be n-2, n and n+2
7 times smallest integer = 7(n - 2) = 7n - 14
Twice largest = 2(n+2) = 2n + 4
Sum of the two is
7n - 14 + 2n + 4 = -91
9n - 10 = -91
9n = -81
n = -81/9 = -9.
So the 3 numbers are -11, -9 and -7
:)