SOLUTION: if an object is dropped off of a tower, the velocity , v, of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the results. express v as a linear f

Algebra ->  Functions -> SOLUTION: if an object is dropped off of a tower, the velocity , v, of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the results. express v as a linear f      Log On


   

Question 77322: if an object is dropped off of a tower, the velocity , v, of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the results. express v as a linear fucntion of t.
Found 2 solutions by jim_thompson5910, chitra:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If the velocity can be obtained by multiplying t by 32 and we add 10 we have
v=32t+10

If you want the equation in function notation then:

v(t)=32t+10

So if t=0, we have an initial velocity of v=10. If v=1, then we have a velocity of v=32+10=42. If we have v=2, then v=32*2+10=64+10=74. In other words, for each second the velocity increases by 32 (notice how 32+42=74). So 32 is our rate of increase and 10 is our initial velocity.

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
The velocity expressed in terms of "t" as a linear function is given by:

v(t) = t * 32 + 10


hence, the solution.