SOLUTION: A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How

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Question 772949: A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%?
$

Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%?
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4000(1+0.039*1) = x(1+0.065*1)
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4000(1.039) = x(1.065)
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x = $3902.35
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Cheers,
Stan H.
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Answer by MathTherapy(10549) (Show Source):
You can put this solution on YOUR website!

A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%?
$

You can do the check!!

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