SOLUTION: How many quarts of pure alcohol must be added to 10 quarts of 10% alcohol solution to obtain a mixture which is 25% alcohol?

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Question 772718: How many quarts of pure alcohol must be added to 10 quarts of 10% alcohol solution to obtain a mixture which is 25% alcohol?
Answer by modi.kk91(20) About Me  (Show Source):
You can put this solution on YOUR website!

let pure alcohol 100%
and quarts=x
x*100%+10*10%=25%(x+10)

after solving


x=2 quarts

by allegation and mixture
let pure alcohol be 100%

10% 100%


25%


100-25=75 and 25-10=15


ratio=75:15=5:1

5:1::10:x

x=2