SOLUTION: can you help me solve x^2+2x+3x+4=70 ? Its the x^2 that confuses me (thats x to the second power) thank you in advance!

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Question 772646: can you help me solve x^2+2x+3x+4=70 ?
Its the x^2 that confuses me (thats x to the second power)
thank you in advance!
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
The x^2 just means x%5E2. That is how you write it using plain text.

Solving this would first need combining the terms of x.
x%5E2%2B5x%2B4=70 ________(2x+3x=5x)
x%5E2%2B5x%2B4-70=0
x%5E2%2B5x-66=0

Can you factorize the left side?
66=6*11
6+11=17
6-11=-5
11-6=5
-6-11=-17
Choice should be obvious.

%28x%5E2%2B5x-66%29=highlight%28%28x-6%29%28x%2B11%29=0%29
Either x-6=0 OR x%2B11=0 so you have two solutions for x.....