Question 772444: A mixture contains 12 Ibs of substance A and 96 Ibs of Substance B. What % is A of the mixture? Found 2 solutions by Cromlix, josmiceli:Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! 12lbs + 96lbs = 108lbs
12/108 * 100 = 11.1%
Substance A is 11.1% of the mixture.
Hope this helps.
:-)
You can put this solution on YOUR website! What you want is: = % of mixture
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A is 11.111 % of the mixture
( this is 11 plus the continuing fraction
.111. . . )
