SOLUTION: Given:AB=BC Prove AC=2BC 1. AB=BC (Given) 2. AB+BC=AC (Segment Addition Postulate) 3. BC+BC=AC (Substitution Property of Equality) 4. 2BC=AC (Distributive Property) 5. AC=2BC

Algebra ->  Geometry-proofs -> SOLUTION: Given:AB=BC Prove AC=2BC 1. AB=BC (Given) 2. AB+BC=AC (Segment Addition Postulate) 3. BC+BC=AC (Substitution Property of Equality) 4. 2BC=AC (Distributive Property) 5. AC=2BC      Log On


   

Question 772440: Given:AB=BC
Prove AC=2BC
1. AB=BC (Given)
2. AB+BC=AC (Segment Addition Postulate)
3. BC+BC=AC (Substitution Property of Equality)
4. 2BC=AC (Distributive Property)
5. AC=2BC (Identity)
Identify the hypothesis, Argument and Conclusion.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The hypothesis is the what you are trying to prove.
in your case, the hypothesis is AC=2BC
The conclusion is the last statement in your proof.
in your case, AC=2BC (Identity)
For a properly completed direct proof, the hypothesis and the conclusion must be identical. Everything in between is argument.