SOLUTION: Find the exact value of the trigonometric function sin(u-v)given that: sin(u)= 5/13 0 < u < pi/2 cos(v)= -3/5 pi/2 < v < pi

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact value of the trigonometric function sin(u-v)given that: sin(u)= 5/13 0 < u < pi/2 cos(v)= -3/5 pi/2 < v < pi       Log On


   

Question 772225: Find the exact value of the trigonometric function sin(u-v)given that:
sin(u)= 5/13
0 < u < pi/2
cos(v)= -3/5
pi/2 < v < pi

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


is in QI, so both sin and cos are positive.











Discard negative because of QI.



Use the same technique to find based on the value of

is in QII, so

Once you have the values for the 4 functions, use those values in the formula for the sine of the difference:



John

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