SOLUTION: {{{ sqrt (6x+7) }}} - {{{ sqrt (3x+3) }}} = 1 I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and

Algebra ->  Rational-functions -> SOLUTION: {{{ sqrt (6x+7) }}} - {{{ sqrt (3x+3) }}} = 1 I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and       Log On


   

Question 77195This question is from textbook
: +sqrt+%286x%2B7%29+ - +sqrt+%283x%2B3%29+ = 1
I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and factor as best I could. So then I had:
+sqrt+%283x%29+ * +sqrt+%282%29+ + 7 - +sqrt+%283x%29+ + +sqrt+%283%29+ = 1
After that, I didn't think that the +sqrt+%283x%29+ could cancel each other out because then there would be no variable, so I am currently stuck right there. I would be really grateful if you let me know if I am on the right track, or if I am really off, help me get on track. Thank you. This question is from textbook

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt (6x+7) - sqrt (3x+3) = 1
Square it the way it is so you end up with just one new radical:
Result of square both sides is:
6x+7 -2sqrt[(6x+7)(3x+3)] + 3x+3 = 1
Isolate the remaining radical:
9x+10 - 2[....] = 1
2[....]= 9x+9
Square to get rid of the radical:
-----
4[(6x+7)(3x+3) = [9(x+1)]^2
Now, solve for x.
I'll leave that to you.
Cheers,
Stan H.